Custom clean step does not work

[lotek]

Hello,

I'd like to add a new custom clean step, removing libraries.
so the "Command" is /bin/rm
"Working directory" is the project directory,
"Command arguments" is the ABSOLUTE path to the lib directory /projects/MyProj/Lib/*

Executing the same command fro any shall removes the library files!

Attempt to execute the cleaning step results in error message like:

The process "/usr/bin/make" exited normally.
Starting: "/bin/rm" /projects/MyPro/Lib/*.so*
/bin/rm: cannot remove `/projects/MyPro/Lib/*.so*': No such file or directory
The process "/bin/rm" exited with code %2.
Error while building project MyPro (target: Desktop)
When executing build step 'Remove Libraries'

Directory and files EXIST and the path is CORRECT!!!

any ideas?

PS
as you definitely noticed I work under LINUX (Suse 11.2)

Thanks for your help

[wysota]

"*" is interpreted by a shell and not by rm. Since the command here doesn't pass through a shell the asterisk is fed directly to rm which doesn't treat it as a wildcard character. You need to enumerate the files directly or use something like 'find . -name "*.so" -delete' as your command. Why would you want to remove files that were not part of the compilation anyway?

[lotek]

Hello,

First, thanks for your readiness to help, but I cant really follow you.
- Shall it mean, that the arguments to the shall call "/bin/rm" are not attached to the call and then executed in a shall? so how it works in this case?
- what is then a "/bin/rm" and how it is called with arguments not processed by the shall?
- I've also tried to execute '/bin/rm /projects/MyProj/Lib/*' and "find" as you suggested written in the "Command Field" without giving an argument, and it also does not work.

By the way, the files in the /projects/MyProj/Lib/, similarly as the /projects/MyProj/Bin/* directory are the part of compilation

with best regards

[wysota]

- Shall it mean, that the arguments to the shall call "/bin/rm" are not attached to the call and then executed in a shall? so how it works in this case?

The command is called directly without the shell.

- what is then a "/bin/rm" and how it is called with arguments not processed by the shall?

I don't understand your question /bin/rm is a binary executable that can be executed the same way as any other binary executable and arguments are passed to it the same way as to every other binary executable. A shell is not required for that.

- I've also tried to execute '/bin/rm /projects/MyProj/Lib/*' and "find" as you suggested written in the "Command Field" without giving an argument, and it also does not work.

Why would it work if you didn't give any arguments?

By the way, the files in the /projects/MyProj/Lib/, similarly as the /projects/MyProj/Bin/* directory are the part of compilation

So just call "make distclean" and forget about your custom clean step.