How to access Quit Slot without aplication pointer...

How can I simple open a program perform some actions and then close it?
Already tried:

Code:

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QTimer::singleShot(10, &a, SLOT(quit()) );

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Inside the mainform... but I do not have access to the application pointer...


Base code for what I want:

Code:

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msgBox.setText("Bla bla bla");
QPushButton *opt1 = msgBox.addButton(tr("First One!"), QMessageBox::ActionRole);
QPushButton *opt2 = msgBox.addButton(tr("Second One!"), QMessageBox::ActionRole);
msgBox.setDefaultButton(opt2);
msgBox.setIcon(QMessageBox::Warning);
msgBox.exec();
 
if(msgBox.clickedButton() == opt1)
{
     //some actions...
     //Close the entire program!
}

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By the way.. we cant forget that Qt still is C++ related so...
this solves everything:

Code:

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exit ( 0 );

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thanks anyway :)

Quote:

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Originally Posted by Cayan

Code:

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exit ( 0 );

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That's a bad way to exit a GUI app. If you need a pointer to your application use QCoreApplication::instance() or the short hand qApp.