cout problem

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cout problem

Hi, I'm printing some values in a loop with this code:

Code:

cout	<< "\tOut" << y << "= " <<output<< "   " ;
cout		 <<  "\terr = " << error << "\t" << " sq_err = " <<  _serrv<< " ";	
cout << "OK";
cout << "\n"; 
// I know this can be done in a line...

Code:

//output
 Out0= 0.9474925         err = 0.05250749         sq_err = 0.001378518 OK
 Out0= 0.6843882         err = 0.3156118  sq_err = 0.04980541
 Out0= 0.8848782         err = 0.1151218  sq_err = 0.006626516 OK
 Out0= 0.7979639         err = 0.2020361  sq_err = 0.0204093 OK
 Out0= 0.9102138         err = 0.08978618         sq_err = 0.004030779 OK

Why does any sq_err appear not tabulated (\t seems hans't effect)

2nd March 2007, 04:11
wysota

Re: cout problem

It has an effect, just the tabulator is one character after the end of the previous text. Look that for "err" rows which are one digit longer "sq_err" fields are tabulated correctly. Either pad (or fill) the err field if it's shorter or calculate the tabulation yourself and add another \t if needed.
2nd March 2007, 08:27
jpn

Re: cout problem

Maybe you could use setw() instead of tabulators?
2nd March 2007, 18:12
Brandybuck

Re: cout problem

Tabs will tab to the next tab column, which are eight spaces wide. If you look at your output, you will see that you are off eight spaces. This is a common problem when trying to line up columns with \t characters.