Trigger QAction by 'Key_Escape'

[Raccoon29]

Hi all,
I'm trying to install a global action for a QWidget that has to be triggered when 'Esc' is pressed.

I try this code:

vClose=new QAction(this);
vClose->setShortcut(Qt::Key_Escape);
connect(vClose,SIGNAL(triggered()),this,SLOT(quickClose()));
addAction(vClose);     // I'm in a QWidget subclass

vClose=new QAction(this);
vClose->setShortcut(Qt::Key_Escape);
connect(vClose,SIGNAL(triggered()),this,SLOT(quickClose()));
addAction(vClose);     // I'm in a QWidget subclass

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but it doesn't work. The function quickClose() is not called.
Instead if I put another key (such as Qt::Key_F4 or Qt::Key_F7, etc...) it gets called normally.
I could understand that Qt::Key_Escape and Qt::Key_Enter behave in a their own way...
So, what is my noobie mistake?

[yogeshm02]

It should work. Are you inside custom widget inherited directly from QWidget or some other class like QDialog? Esc key might already be being used by that.

[Raccoon29]

It should work. Are you inside custom widget inherited directly from QWidget or some other class like QDialog? Esc key might already be being used by that.

No, before was inherited from QDialog, but since there Esc forces the dialog to close (as expected by QDialog), I changed its ancestor and now the class is inherited directly from QWidget:

class frmcontact:public QWidget

class frmcontact:public QWidget

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The fact that other keys work but not Esc and Enter is strange...
thank you for the suggestion, any other idea or I have to try reimplementing onKeyPress (such a bad thing here...)?

[jpn]

You should be using QShortcut:

#include <QtGui>
 
int main(int argc, char* argv[])
{
    QApplication app(argc, argv);
    QWidget w;
    new QShortcut(Qt::Key_Escape, &w, SLOT(close()));
    w.show();
    return app.exec();
}

#include <QtGui>

int main(int argc, char* argv[])
{
    QApplication app(argc, argv);
    QWidget w;
    new QShortcut(Qt::Key_Escape, &w, SLOT(close()));
    w.show();
    return app.exec();
}

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[Raccoon29]

You should be using QShortcut:

#include <QtGui>
 
int main(int argc, char* argv[])
{
    QApplication app(argc, argv);
    QWidget w;
    new QShortcut(Qt::Key_Escape, &w, SLOT(close()));
    w.show();
    return app.exec();
}

#include <QtGui>

int main(int argc, char* argv[])
{
    QApplication app(argc, argv);
    QWidget w;
    new QShortcut(Qt::Key_Escape, &w, SLOT(close()));
    w.show();
    return app.exec();
}

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Thank you, even if I discovered that my solution worked too (so falled for some internal troubles that I'm going to investigate about), using QShortcut seems much more clear for this job.

[Raccoon29]

Ok, I solved it.
All has been caused by a shortcut that I set in QtDesigner... and I forgot...

So if QActions are not triggered, it is most because it encountered conflicts when triggering.
So take a look to all QAction implementations

Hope to be usefull for someone else.