Memory could not be read? (runtime) [solved]

[DrDonut]

Hi, ^NyAw^

Thank you for your reply, and for pointing out that it probably had to do something with pointers, you where right.

Thing was that I tried to add widgets to a grid but had not used the line:

grid = new QGridLayout;

grid = new QGridLayout;

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And I also found a connect statement for a timer that didn't exist.

Thanks for your help!

DrDonut