Originally Posted by MrDeath you dont have to cast it... widget->show() will do No a Widget instance do not know the show method. The compiler refuses it
Originally Posted by ber0y No a Widget instance do not know the show method. The compiler refuses it yeah... my fault... you have named your class as widget... that confused me...
Frameless Window Helper
yeah because when i created it i subclassed QWidget! ;-) thanks wagmare too !
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