Value changed in a QTableView field

[nittalope]

I've searched a bit, but could not found how to do this.

Have got a QSqlTableModel and a QTableView which I use to show the data.
I would like to know if, when I change the value of a field in QTableView, a signal is emitted, because I need to call a function when the user edit a field.

Don't care, now, to change the data directly in database, I'll do the commit manually.

[john_god]

I never used QSqlTableModel, but as far as QTableView if you want users to edit data I think you should use QTableWidget instead. Assuming you're using QTCreator just right clik on QTableWidget choose 'Go to Slot... ' option, and a list with Signal will apear. I think QTableWidget::itemChanged ( QTableWidgetItem * item ) will do.

[wysota]

For every model the QAbstractItemModel::dataChanged() signal is emitted when contents of the model change. So simply go through QAbstractItemView::model() to find the appropriate signal and connect to it.

[franz]

I never used QSqlTableModel, but as far as QTableView if you want users to edit data I think you should use QTableWidget instead.

Just a remark here: QTableWidget is basically a QTableModel a filter and a QTableView put into one convenience widget. When the model supports data for the Qt::EditRole, then QTableView will be perfectly able to support editing of data.

[nittalope]

@wysota:
thank you! that was what I was looking for!

@john_god:
franz is right, no problem at all editing data in QTableView!

By the way here is how I solved it:

myModel = new QSqlRelationalTableModel(this);
 
    connect(myModel, SIGNAL(dataChanged(QModelIndex,QModelIndex)), this, SLOT(myFunction()));

myModel = new QSqlRelationalTableModel(this);

    connect(myModel, SIGNAL(dataChanged(QModelIndex,QModelIndex)), this, SLOT(myFunction()));

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and then I implemented myFunction() to do what I need to do