How to access the UI from another class ?

[squidge]

class CA {
public:
void log (QString *str);
};
 
class CB {
public:
void log (QString *str);
};
 
CA firstclass;
CB secondclass;
 
void CA::log(QString *str) {
secondclass.log("foo");
}
 
void CB::log(QString *str) {
ui->LOG->append(str);
}

class CA {
public:
void log (QString *str);
};

class CB {
public:
void log (QString *str);
};

CA firstclass;
CB secondclass;

void CA::log(QString *str) {
secondclass.log("foo");
}

void CB::log(QString *str) {
ui->LOG->append(str);
}

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You can also have firstclass and secondclass as pointers by using new to initialise them and use -> instead of '.'

[fitzy]

I don't get it.

I have pasted your example (by the way, I think you meant CA::log(QString *str) not A::log(QString *str) ) but it doesn't work.

There are many errors :

ISO C++ forbids declaration of `log' with no type
CA::log(QString*)' does not match any in class `CA'
ISO C++ forbids declaration of `log' with no type
etc

ISO C++ forbids declaration of `log' with no type
CA::log(QString*)' does not match any in class `CA'
ISO C++ forbids declaration of `log' with no type
etc

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