QTcpServer : retrieve the requested URL

[fitzy]

Hi there!

I have developped a server, its address is 127.0.0.1:4242 ; I'm using QTcpServer, and QTcpSocket (to send the answer).

I would like to be able to know what is the requested URL.

For example, if I type this in Firefox :

http://127.0.0.1:4242/directory1/test/

http://127.0.0.1:4242/directory1/test/

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how can I know that firefox wants to access /directory/test/ ?

I tried localAddress(), but it only returns 127.0.0.1



I really need your help guys !