Given the initial comments posted to the thread, I expected this thread to die, but it has not. I thought that moderator might move the thread to the General thread, but it is still here, so....

You can directly call a method for a specific class in C++ providing you have visibility to see the class and the method in the class. The example that I provided to the original poster using a direct email is as follows:

Qt Code: 
  1. class LTop
  2. {
  3. public:
  4.     virtual void notInMid() const
  5.     {
  6.         qDebug("Method LTop::notInMode()");
  7.     }
  8.     virtual void allDo() const
  9.     {
  10.         qDebug("Method LTop::allDo()");
  11.     }
  12. };
  13. class LMid : public LTop
  14. {
  15.     typedef LTop Base;
  16. public:
  17.     virtual void allDo() const
  18.     {
  19.         Base::allDo();
  20.         qDebug("Method LMid::allDo()");
  21.     }
  22. };
  23. class LBottom : public LMid
  24. {
  25.     typedef LMid Base;
  26. public:
  27.     virtual void notInMid() const
  28.     {
  29.         //Cannot make this call because it does not exist
  30.         //Base::notInMid();
  31.         //Only works if there is public inheritance.
  32.         LTop::notInMid();
  33.         qDebug("Method LBottom::notInMode()");
  34.     }
  35.     virtual void allDo() const
  36.     {
  37.         //this->LMid::allDo();
  38.         Base::allDo();
  39.         qDebug("Method LBottom::allDo()");
  40.     }
  41. };
To copy to clipboard, switch view to plain text mode 

Notice a few things that allow this to work

  1. Public inheritance is used. Using "class LMid : LTop" rather than "class LMid : public LTop" prevents LBottom from referencing a method in LTop, but still allows LMid to reference LTop.
  2. The methods must have visibility. In this example, I used public:
  3. You cannot call a method directly that does not exist. Consider the method "notInMid". The method is not implemented in LMid. I dislike that in LBottom I cannot simply say "call the next one up in the heirarchy". I am sure that this is because C++ supports multiple inheritance, so it is not obvious what to call unless you explicitly specify it.

The probably enough for now.