udp receive data problem

[ChrisW67]

You are assuming that the transmitted array is transmitted as a single datagram and arrives as a single datagram etc. If it arrives in pieces you do nothing to accumulate the pieces (ba is discarded between while loops).

Are you sure that QDataStream's serialisation format for float is the sames as the sender's?
Is a LabView CVI float the same size and format as a C++ float?
Is there actually data in your byte array?
Is the data block just a pure list of float values, or is there an envelope structure/checksum/block size?
Are you sure the zero or inf are not the values being sent?

[zxwmail]

hi,chrisw67,thanks your reply.
the udp client(delphi/indy ) can received correct values,i want to use qt to replace my delphi program.

Are you sure that QDataStream's serialisation format for float is the sames as the sender's?

so i think the problem is data format .
But I can't think of a better idea,
how to ?somebody can help me?

[squidge]

As Chris says, you may receive your datagram in multiple chunks.

Secondly, UDP is not meant to be reliable, so you may receive some data in duplicate and some data not at all.

If you want to use QDataStream, then you should use the same Qt version for both sender and receiver, to ensure compatibility.

[ChrisW67]

You have the data in a QByteArray. You can get a char* to the internal data buffer. You can cast that to float* if you are certain that the byte ordering is the same, and the 'float' data sent is the same format as a C++ float (not a double).

[zxwmail]

float* ft=ba.data();
float dat=*(ft+x);

but andbody have a Perfect solution use qt?

[squidge]

We don't know how the data is internally formatted, so we can't tell you the best way.

[zxwmail]

hi,squidge,thanks your reply,but my english is bad.
qbytearray's data type is char* ,i want to convert from char* to float array,because udp received data is float array.
if I run

float* ft=ba.data();
float dat=*(ft+x);

float* ft=ba.data();
float dat=*(ft+x);

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then
result is correct,but this is c,not c++,not qt,I believe a best way to do it with qt.

[ChrisW67]

What you have there won't compile without error as C or C++. This has nothing to do with Qt once you have a char* to the data in memory:

// Create some dummy data
QByteArray ba;
ba.fill(0, 10 * sizeof(float));
unsigned int size = ba.size();
char* c = ba.data();    
// OR const char* cc = ba.constData();
// Make sure that ba stays in scope while you do this
// Nothing Qt below here
 
 
float* ft = reinterpret_cast<float*>(c); 
// OR const float* ft = reinterpret_cast<const float*>(cc);
for (unsigned int i = 0; i < size/sizeof(float); ++i) {
  std::cout << *ft++ << std:endl;
}

// Create some dummy data
QByteArray ba;
ba.fill(0, 10 * sizeof(float));
unsigned int size = ba.size();
char* c = ba.data();    
// OR const char* cc = ba.constData();
// Make sure that ba stays in scope while you do this
// Nothing Qt below here


float* ft = reinterpret_cast<float*>(c); 
// OR const float* ft = reinterpret_cast<const float*>(cc);
for (unsigned int i = 0; i < size/sizeof(float); ++i) {
  std::cout << *ft++ << std:endl;
}

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The caveats regarding byte order, float/double etc still apply. If it breaks you get to keep the pieces

[squidge]

I believe a best way to do it with qt.

A better way in Qt is to use the streaming operators, but we don't know if these will be compatible with what you are creating at the "other end", so you may have to do something like that (or like what Chris states) to get the values you want