How to present a Qt GUI app window to users???

**wshn13** · 16th August 2011, 04:36

Now I have a Qt GUI app called A, and another we can call it B. Then I launch A, and launch B,in this case ,A window is behind B, we can send dbus message to A. The question is :How can I show A up to me ???

**nish** · 16th August 2011, 08:51

once u get the dbus message,

Qt Code:

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QWidget::activateWindow ()

QWidget::activateWindow ()

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**wshn13** · 29th August 2011, 07:27

Originally Posted by nish

once u get the dbus message,

Qt Code:

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QWidget::activateWindow ()

QWidget::activateWindow ()

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thans for your answer ,but what you said dose not work ,when my window stay behind another window , I send dbus message to it, then it invoke activateWindow ,but my window still stay behind other window!

**wysota** · 29th August 2011, 07:57

QWidget::raise()

**wshn13** · 29th August 2011, 09:34

I have a app with GUI ,I want it to show to front when the app receive a dbus message,but the app can't do like it now , I have attach it ,you can download it, modify my code,thanks!
PS:when I want it show front i send "dbus-send / com.test.clip.show" the app's session name is com.test.clip