Hi,

I'm trying to show a new window after clicking in the menu. I'm creating the windows as a new component. Something like this:

Qt Code: 
  1. onTriggered: {
  2.  
  3.                     var component = Qt.createComponent("Info.qml");
  4.                     if (component.status == Component.Ready) {
  5.                         /*
  6.                         * The created object will become a child of the appWindow
  7.                         * item in main.qml.
  8.                         */
  9.                         var object = component.createObject(mainWindow);
  10.                         object.show()
  11.                     } else if (component.status == Component.Error) {
  12.                         // Error Handling
  13.                         console.log("Error loading component:", component.errorString());
  14.                     }
  15.                 }
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Info.qml:

Qt Code: 
  1. Window {
  2.         id: info
  3.         title: qsTr("Info")
  4.  
  5.         width: 340
  6.         height: 280
  7.         visible: true
  8.  
  9.         Text {
  10.             text: "Hello World!"
  11.             font.pointSize: 24
  12.         }
  13. }
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If I launch the desktop application everything goes well, but if I launch the application in my Android emulator, when I press the menu, I don't see the window.

It seems it is created because I cannot continue using the application unless I press ESC in the keyboard. I guess that ESC is closing the window.