QUpdSocket The program has unexpectedly finished.

[anda_skoa]

What I was trying to hit at is that you need to create an instance of QTimer if you want to use it
Right now you are using an uninitialized pointer.

Cheers,
_

[ariad]

Thanks!!!! I can send and receive!!!


Now I have the next problem, but why I can't do this?

ui->label_2->setText(datagram.at(i).toString());

ui->label_2->setText(datagram.at(i).toString());

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Build:
Request for member 'toString' in 'datagram.QByteArray::at(i), which is of non-class type char
ui->label_2->setText(datagram.at(i).toString());

Thanks another time!!

[anda_skoa]

QByteArray::at() returns a char, a single character. It is not a class and does not have any methods.

If you want to display the string inside the byte array, use one of the QString::fromXYZ methods, e.g. QString::fromAscii()

Cheers,
_

[ariad]

Ok, thanks!!!