I have discovered something with a ternary statement that I don't quite understand.
If I use a normal if - else construct I have no problem in compiling, however using the same variables in a ternary statement I get a Invalid conversion from int to constant char* error.

Here is my code:

Header file

Qt Code: 
  1. #ifndef TERNARYTEST_H
  2. #define TERNARYTEST_H
  3. #include <QString>
  4. #include <QDebug>
  5. #include <QRegExp>
  6.  
  7. typedef QMap<QString, QVariant> MyMap;
  8.  
  9. void setup(void);
  10. bool isInt(QString);
  11.  
  12. #endif // TERNARYTEST_H
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and the main file

Qt Code: 
  1. #include <QCoreApplication>
  2. #include <ternaryTest.h>
  3.  
  4. int main(int argc, char *argv[])
  5. {
  6.     QCoreApplication a(argc, argv);
  7.     setup();
  8.     return a.exec();
  9. }
  10.  
  11. void setup()
  12. {
  13.     MyMap map;
  14.  
  15.     QString str = "Release Time: 2000";
  16.     QString val;
  17.     QString key;
  18.     bool ok;
  19.     val = (str.section(':',1,-1)).trimmed();
  20.     key = (str.section(':',0,0)).toUpper().trimmed();
  21.     qDebug()<<val;
  22.     qDebug()<<key;
  23.  
  24.     if ( isInt(val) )
  25.         map[key] = val.toInt();
  26.     else
  27.         map[key] = val;
  28.  
  29.     qDebug()<<map;
  30.  
  31.     map[key] = isInt(val) ? val.toInt(&ok, 10) : val; /// Error compiling here
  32.  
  33.  
  34.     exit(0);
  35. }
  36.  
  37. bool isInt(QString s)
  38. {
  39.     QRegExp re("\\d*");
  40.     return re.exactMatch(s);
  41. }
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As the if - else constructs works fine I have no problem. Just curious as to the compiler error on the ternary statement.

The object of the program is to use everything before the first occurrence of a colon as a key in a QMap and everything after, including any colons as a QVariant value (Int or QString).

Thanks in advance.
Regards
Graham Benney