emit a signal into an MdiSubWindow

[anda_skoa]

Why so complicated?

Why not just call updateMoveState directly from send_move_signal?

Cheers,
_

[Qtdigitex]

Thanks for your answer ,

I just started learning to make Mdi Apps ,

so, yes my solutions might be complicated

how can i do it ??

I tried this :

def send_move_signal(self):
    currentMdi = self.mdiArea.activeSubWindow()
    currentMdi.updateMoveState()

def send_move_signal(self):
    currentMdi = self.mdiArea.activeSubWindow()
    currentMdi.updateMoveState()

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But Got error : " QMdiSubWindow " has no attribute updateMoveState

If i created an instance to the last opened MdiSubWindow it will work only on the last one but i want this signal to act on the current active Window

Thanks,

[anda_skoa]

Ah, I would have assumed that Python's duck typing would recognize the method in your subclass.

Then, how about this:
- connect the button to all MdiWid instances
- inside updateMoveState() you check if this is the active window. If yes you do something, if not you ignore the method call

Cheers,
_

[Qtdigitex]

- connect the button to all MdiWid instances
_

i don't create an instance for each Opened MdiSubWindow , and i think we must not do it.

The main problem here for me is to acess to the Currently Active Mdi Widget Methods ..

[anda_skoa]

i don't create an instance for each Opened MdiSubWindow , and i think we must not do it.

That doesn't make any sense.

You have an instance of your sub window class for every sub window.
A window that doesn't exist isn't there at all.

The main problem here for me is to acess to the Currently Active Mdi Widget Methods ..

In C++ that would be a cast, look for whatever mechanism Python uses for such type conversions.

Cheers,
_

[Qtdigitex]

here's the function that load the document ( QWidget ) :

def load(self):
    ImageProject = OIWid()
    self.mdiArea.addSubWindow(ImageProject)

def load(self):
    ImageProject = OIWid()
    self.mdiArea.addSubWindow(ImageProject)

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i skipped details , but that's it. it's the code that load my widget.

if i make ImageProject an instance variable of my main class ( QMainWindow ) : self.ImageProject instead of ImageProject,

the last opened Project would be self.ImageProject and not the current active window !

[anda_skoa]

In you first post you had a class MdiWid, but I can't see that being used in your newest code snippet.

Cheers,
_

[Qtdigitex]

Hi , i finaly found the solution :

i only needed to use the QMdiSubWindow's method : widget() to be able to acess my currently opened widget's methods and signals ...

SO it will become :

self.mdiArea.activeSubWindow().widget().update_move_state()

self.mdiArea.activeSubWindow().widget().update_move_state()

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instead of :

self.mdiArea.activeSubWindow().update_move_state()

self.mdiArea.activeSubWindow().update_move_state()

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