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Thread: How to declare attribute 'noreturn'

  1. #1
    Join Date
    Jun 2016
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    Default How to declare attribute 'noreturn'

    I just opened a project in QT Creator 4.9 and in the application .cpp I get a warning that this function could include attribute 'noreturn', but I have not found how to declare this. I find examples of code such as:

    [[ noreturn ]] void f() {
    throw "error";
    // OK

    void q [[ noreturn ]] (int i) {
    // behavior is undefined if called with an argument <= 0
    if (i > 0) {
    throw "positive";

    but no clue as to where this goes--in the function .cpp? or the main.cpp? before the function? within the function?
    and I'm not at all familiar with the syntax [[ something ]].

    Or does it even matter whether the attribute is declared or not?


  2. #2
    Join Date
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    Brisbane, Australia
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    Default Re: How to declare attribute 'noreturn'

    The items between [[ ]] in a function (variable...) declaration are attributes that provide the compiler with extra information about the item they are attached to. The compiler can use these in a range of ways. The "noreturn" attribute has been around since C++ 11.

    [[ noreturn ]] attached to a function declaration informs the compiler that control will not return from the function (as in the case of an unconditional throw()). They go in the first declaration of the function. If f() is declared in a header file then this is the place to put it. If the function exists only in a single CPP file, i.e. it is private, with no other declaration then it goes there.

    The second code snippet you posted is an example that can lead to undefined behaviour, i.e. returning from a function you explicitly declared would not return control.

    Qt Code:
    1. // >>> function.h
    2. #ifndef FUNCTION_H
    3. #define FUNCTION_H
    5. [[ noreturn ]] void f();
    6. void g();
    8. #endif // FUNCTION_H
    10. // >>> function.cpp
    11. #include <iostream>
    12. using namespace std;
    14. #include "function.h"
    16. void f() {
    17. cout << "No return" << endl;
    18. throw 1;
    19. }
    21. void g() {
    22. cout << "No return" << endl;;
    23. throw 1;
    24. }
    26. // >>> main.cpp
    27. #include <iostream>
    28. using namespace std;
    30. #include "function.h"
    32. [[ noreturn ]] void h() {
    33. cout << "No return" << endl;
    34. throw 3;
    35. }
    37. int main(int argc, char **argv) {
    38. cout << "Before f()" << endl;
    39. f();
    40. // this should be unreachable code
    41. cout << "Before g()" << endl;
    42. g();
    43. cout << "Before h()" << endl;
    44. h();
    45. }
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    Functions f() and g() have identical function code but, because the compiler knows that f() will not return, it may generate different code for these function or calls to them. In my experiments with GNU C++ there is no code generated for the calls to g() and h() because they cannot be reached after a call to f().

  3. #3
    Join Date
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    Alameda, CA, USA
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    Default Re: How to declare attribute 'noreturn'

    In my experiments with GNU C++ there is no code generated for the calls to g() and h() because they cannot be reached after a call to f().
    Wow, that seems like a recipe for descent into debugging hell and unsupportable code. What looks like perfectly acceptable code isn't, but that cannot be determined unless you are aware of the declaration of f().
    <=== The Great Pumpkin says ===>
    Please use CODE tags when posting source code so it is more readable. Click "Go Advanced" and then the "#" icon to insert the tags. Paste your code between them.

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