error in Python script

[HanyM.Magdy]

I have write a program to run python script [python2.4] under CentOS with Qt4.7

class QPython
{
private:
    QString strScript;
public:
    QPython(){}
    QPython(QString _strScript)
    {strScript  = _strScript;}
    ~QPython(){}
    int PythonInitialize()
    {
        Py_Initialize();
        return Py_IsInitialized();
    }
    int process_expression(char* cScript)
    {
        return PyRun_SimpleString(cScript);
    }
    void PythonFinalize()
    {Py_Finalize();}
};

class QPython
{
private:
    QString strScript;
public:
    QPython(){}
    QPython(QString _strScript)
    {strScript  = _strScript;}
    ~QPython(){}
    int PythonInitialize()
    {
        Py_Initialize();
        return Py_IsInitialized();
    }
    int process_expression(char* cScript)
    {
        return PyRun_SimpleString(cScript);
    }
    void PythonFinalize()
    {Py_Finalize();}
};

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i have an error
mainwindow.o: In function `QPython::PythonInitialize()':
/root/Desktop/PythonInterpreter/QPython.h:20: undefined reference to `Py_Initialize'
/root/Desktop/PythonInterpreter/QPython.h:21: undefined reference to `Py_IsInitialized'
mainwindow.o: In function `QPython:: process_expression(char*)':
/root/Desktop/PythonInterpreter/QPython.h:25: undefined reference to `PyRun_SimpleString'
mainwindow.o: In function `QPython::PythonFinalize()':
/root/Desktop/PythonInterpreter/QPython.h:28: undefined reference to `Py_Finalize'
collect2: ld returned 1 exit status

i need to solve it, i search with google and i don't find the solution for it, i see the solution for DevC++.
Thanks Hany

[alexisdm]

If you compile with qmake, you should have a line like this in your .pro file

LIBS += -lpython2.4

LIBS += -lpython2.4

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