"new" modifier explicitly hide a member inherited from a base class in C#

[kunalnandi]

What do you mean exactly by "hidden from the base MyBaseC"? But it seems that you just want the default behaviour of non-virtual methods:

#include <iostream>
 
class Base
{
   public:
      void foo() { std::cout<< "Base::foo" << std::endl; }
      virtual void bar() { std::cout<< "Base::bar" << std::endl; }
};
 
class Derived : public Base
{
   public:
      void foo() { std::cout<< "Derived::foo" << std::endl; }
      virtual void bar() { std::cout<< "Derived::bar" << std::endl; }
};
 
int main()
{
   Derived d;
   Base *b = &d;
 
   d.foo();
   b->foo(); // <--
 
   d.bar();
   b->bar();
 
   return 0;
}

#include <iostream>

class Base
{
   public:
      void foo() { std::cout<< "Base::foo" << std::endl; }
      virtual void bar() { std::cout<< "Base::bar" << std::endl; }
};

class Derived : public Base
{
   public:
      void foo() { std::cout<< "Derived::foo" << std::endl; }
      virtual void bar() { std::cout<< "Derived::bar" << std::endl; }
};

int main()
{
   Derived d;
   Base *b = &d;

   d.foo();
   b->foo(); // <--

   d.bar();
   b->bar();

   return 0;
}

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Output:

Hello,

d->bar();

this will call the member function of Derived class...
but, wht is want is.. member function of Derived class Derived::bar() should be hidden from the derived class object.... and the object of Derived class should called Base::bar() member function...

this is possible in C# if we declare the derived class member function like as follow...


// In C#
class Base
{
public:
void foo() { std::cout<< "Base::foo" << std::endl; }
virtual void bar() { std::cout<< "Base::bar" << std::endl; }
};

class Derived : public Base
{
public:
void foo() { std::cout<< "Derived::foo" << std::endl; }
new void bar() { std::cout<< "Derived::bar" << std::endl; } <---
};


int main()
{
Derived d;

d.bar(); <---

return 0;
}

Output:

Base::bar();