Allow Many QWidgets to be Shown into One QWidget ?

[jpn]

Sounds like you created the form as a child of the stacked widget but you didn't actually add the widget to the stack widget. That's at least one reason why it wouldn't be managed by the stacked widget.

[Fatla]

How is that ?!!

Part of Header files 's code generated to the form that contains the QStackedWidget :

#include <QtGui/QStackedWidget>
#include <QtGui/QWidget>
 
 
class Ui_FormTwo
{
public:
    QStackedWidget *stackedWidget;
    QWidget *page;
 
    void setupUi(QWidget *FormTwo)
    {
    stackedWidget = new QStackedWidget(FormTwo);
    stackedWidget->setObjectName(QString::fromUtf8("stackedWidget"));
    stackedWidget->setGeometry(QRect(460, 130, 551, 371));
    page = new QWidget();
    page->setObjectName(QString::fromUtf8("page"));
    page->setGeometry(QRect(0, 0, 551, 371));
    stackedWidget->addWidget(page);
 
    retranslateUi(FormTwo);
 
    stackedWidget->setCurrentIndex(0);
 
 // ......................etc
 
    } // setupUi

#include <QtGui/QStackedWidget>
#include <QtGui/QWidget>


class Ui_FormTwo
{
public:
    QStackedWidget *stackedWidget;
    QWidget *page;

    void setupUi(QWidget *FormTwo)
    {
    stackedWidget = new QStackedWidget(FormTwo);
    stackedWidget->setObjectName(QString::fromUtf8("stackedWidget"));
    stackedWidget->setGeometry(QRect(460, 130, 551, 371));
    page = new QWidget();
    page->setObjectName(QString::fromUtf8("page"));
    page->setGeometry(QRect(0, 0, 551, 371));
    stackedWidget->addWidget(page);

    retranslateUi(FormTwo);
    
    stackedWidget->setCurrentIndex(0);

 // ......................etc
    
    } // setupUi

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---------------------------------------------------------------
Temporarily , I've added the code that add my .UI to the stack at the constructor of the form that has the stack object :

CustomSlot2::CustomSlot2(QWidget *parent): QWidget(parent)
{
	formTwo.setupUi(this);
 
	CustomSlot *CustomSlotObj=new CustomSlot()  ;
 
	formTwo.stackedWidget->insertWidget(1,CustomSlotObj);
 
        QWidget *WidgetObj;
	WidgetObj= formTwo.stackedWidget->widget (1) ;
 
        WidgetObj->show();
 
 
}

CustomSlot2::CustomSlot2(QWidget *parent): QWidget(parent)
{
	formTwo.setupUi(this);

	CustomSlot *CustomSlotObj=new CustomSlot()  ;

	formTwo.stackedWidget->insertWidget(1,CustomSlotObj);

        QWidget *WidgetObj;
	WidgetObj= formTwo.stackedWidget->widget (1) ;

        WidgetObj->show();


}

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Thanks .

[jpn]

Aha, now I realized what's wrong.

QWidget *WidgetObj;
WidgetObj= formTwo.stackedWidget->widget (1) ;
 
WidgetObj->show();

QWidget *WidgetObj;
WidgetObj= formTwo.stackedWidget->widget (1) ;

WidgetObj->show();

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This is not the way you use QStackedWidget. You are supposed to use QStackedWidget::setCurrentIndex() or setCurrentWidget().

[Fatla]

Thanks , it works successfully .
I 've one more question :

- I've added many QWidgets into stack . Now I need when the turn comes to a particular widget to be shown , I can access its variables .

#include "Container.h"
 
 
 
Container::Container(QWidget *parent): QWidget(parent)
 {
    ContainerUi.setupUi(this);
 
	PageIndex=1;
 
 
	CustomSlot1 *CustomSlot1Obj =new CustomSlot1();
	CustomSlot2 *CustomSlot2Obj=new CustomSlot12();
	CustomSlot3 *CustomSlot3Obj=new CustomSlot3();
//........................ to CustomSlot9
 
 
    // Push objects into the QStackedWidget
	ContainerUi.StackedWidget->addWidget(CustomSlot1);
	ContainerUi.StackedWidget->addWidget(CustomSlot2);
	ContainerUi.StackedWidget->addWidget(CustomSlot3);
//.................. pust the other Widgets into the Stack
 
 
	ContainerUi.StackedWidget->setCurrentIndex(PageIndex);
	PageIndex++;
 
}
 
void Container :: NextPage()
{
 
 
 
	int CurrentIndex=ContainerUi.StackedWidget->currentIndex ();
	if(PageIndex <10)
	{
 
		if(CurrentIndex==3 )
		{
		CustomSLot3 *widget ;
		widget=ContainerUi.StackedWidget->widget  (3);
                                  // GrainSizeFlag is a public variable at CustomSlot3
				if(widget->GrainSizeFlag==true)
				::PageIndex=7;
 
 
 
		}
		ContainerUi.StackedWidget->setCurrentIndex(PageIndex);
		PageIndex++;
 
	}
 
 
}

#include "Container.h"



Container::Container(QWidget *parent): QWidget(parent)
 {
    ContainerUi.setupUi(this);

	PageIndex=1;
    
	
	CustomSlot1 *CustomSlot1Obj =new CustomSlot1();
	CustomSlot2 *CustomSlot2Obj=new CustomSlot12();
	CustomSlot3 *CustomSlot3Obj=new CustomSlot3();
//........................ to CustomSlot9


    // Push objects into the QStackedWidget
	ContainerUi.StackedWidget->addWidget(CustomSlot1);
	ContainerUi.StackedWidget->addWidget(CustomSlot2);
	ContainerUi.StackedWidget->addWidget(CustomSlot3);
//.................. pust the other Widgets into the Stack


	ContainerUi.StackedWidget->setCurrentIndex(PageIndex);
	PageIndex++;

}

void Container :: NextPage()
{
	


	int CurrentIndex=ContainerUi.StackedWidget->currentIndex ();
	if(PageIndex <10)
	{
		
		if(CurrentIndex==3 )
		{
		CustomSLot3 *widget ;
		widget=ContainerUi.StackedWidget->widget  (3);
                                  // GrainSizeFlag is a public variable at CustomSlot3
				if(widget->GrainSizeFlag==true)
				::PageIndex=7;
			
			
			
		}
		ContainerUi.StackedWidget->setCurrentIndex(PageIndex);
		PageIndex++;

	}


}

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By default the Stack contains one widget . So my "CustomSlot" 'll go to the index [1].
As a result of that , CustomSlot3 'll go to index [3].

I've an error that tells ms : Invalid Conversion QWidget* to CustomSlot3*

Thanks .

[wysota]

I suggest you keep all pointers as member variables of the containing class and access them directly instead of fetching the pointer through current widget of the stack (it is possible of course - you'd have to cast the pointer received to a proper type).

[Fatla]

It has been a long time since my last reply .
Things were going so fine & the resources over web were extremely helpful .

Currently , I was looking for property/function that DeActivate child widget
(e.g. If I've a Widget that has a QPushButton . When the user press that button another widget 'll be shown & TOTALLY DeActivate the previouse widget .
So the user won't be able even to close / maximize/minimize the old widget )

I've tried :
isActiveWindow():Just make the widget on top .
setEnabledisable all the controls into widget but not the toolbar (i.e. the user will be able to close / maximize/minimize widget)

Thanks .

[Fatla]

I've found a solution to the problem :

this->setEnabled(false);
 
   HMENU menu = ::GetSystemMenu(this->winId(), FALSE);
 
   ::DeleteMenu(menu, SC_CLOSE, MF_BYCOMMAND);
 
   ::EnableMenuItem(menu, SC_CLOSE, MF_BYCOMMAND | MF_GRAYED);

this->setEnabled(false);

   HMENU menu = ::GetSystemMenu(this->winId(), FALSE);

   ::DeleteMenu(menu, SC_CLOSE, MF_BYCOMMAND);

   ::EnableMenuItem(menu, SC_CLOSE, MF_BYCOMMAND | MF_GRAYED);

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That of course after including : #include <qt_windows.h>

[Fatla]

I've solved the 2nd issue by :

void MainWindow::EnableToolBar()
 {
	 MainWindowMenu = ::GetSystemMenu(this->winId(), TRUE);
 
 }

void MainWindow::EnableToolBar()
 {
	 MainWindowMenu = ::GetSystemMenu(this->winId(), TRUE);

 }

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[wysota]

Why would you want to disable maximizing/minimizing a window? Don't you think it is an extreme interference in the user's desktop? As for closing, you don't need any windows related functions, simply reimplement closeEvent() for your widget and ignore the event if you want to prevent the window from being closed. You can disable the maximize/minimize buttons if you really want to, by either hiding them using window flags or by removing the window from the window manager's control (by using window flags again). To disable the contents of a window simply disable() it (or setEnabled(false)).