question on connect

[mickey]

Hello everybdy. I'm understand the real problem; this is my code
Every time the openLightDialog() is called, it seems the connect below is duplicated: the SLOT starts many time how I called openLightDialog(); eg if I call openLightDialog() 3 times, when a signal occurs, activeTabLight(int) is called 3 time instead one; I tried to put a disconnect at the end (but I don't like it). Furthermore, it seems that disconnect conficlits with a connect inside myLightDialog() constructor....

myLightDialog::myLightDialog( QWidget* parent, const char* name, bool modal, WFlags fl )
	:lightDialog (parent, name, modal, fl)  {		
		connect (this->buttonGroupLL, SIGNAL(clicked(int)), this, SLOT(pushButtonLight(int))); // with disconnect at the end, this doesn't work!!
}

myLightDialog::myLightDialog( QWidget* parent, const char* name, bool modal, WFlags fl )
	:lightDialog (parent, name, modal, fl)  {		
		connect (this->buttonGroupLL, SIGNAL(clicked(int)), this, SLOT(pushButtonLight(int))); // with disconnect at the end, this doesn't work!!
}

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void myMainForm::openLightDialog() {
   vector <QCheckBox*> cbl;
   cbl.push_back(lightd->checkBoxL0);
   ................................
   for (int i=0; i<8; i++) 
	connect(cbl[i], SIGNAL(stateChanged(int)), this, SLOT(activeTabLight(int)));
   if(lightd->exec()){
       DoSomething();
      ......................
   }
   for (int i=0; i<8; i++) {
 	cbl[i]->disconnect();
   }

void myMainForm::openLightDialog() {
   vector <QCheckBox*> cbl;
   cbl.push_back(lightd->checkBoxL0);
   ................................
   for (int i=0; i<8; i++) 
	connect(cbl[i], SIGNAL(stateChanged(int)), this, SLOT(activeTabLight(int)));
   if(lightd->exec()){
       DoSomething();
      ......................
   }
   for (int i=0; i<8; i++) {
 	cbl[i]->disconnect();
   }

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How to do this? maybe Do I have to destroy that vector anywhere?
thanks