How to get a pointer to a QObject's property ?

[HiJack]

Did you check the source? See QObject:roperty() and QMetaProperty::read() for the dirty details.

Ya I do have seen back to QMetaProperty, but thers's no way to help me to get the member's address unless you modify the moc file. ( seems like anti-oop, hur? )
I can enumerate the children list of one QObject object, but first I must set each member's parent, and second there's no one child pointer if the member's type is int, or QString, bool, etc. so I gave up this way.
Another suggestion?

[HiJack]

solved manually. you guys.

[wysota]

Properties are not QObjects and don't have addresses. I think your whole concept is flawed because of a wrong assumption. If you'd like to get an address to a value of a property, it still wouldn't have worked as QVariant (which stores the value) is implicitly shared and thus the place in memory holding the value may vary in time (and you'd get a stale pointer). If you want to have a property which is QObject then that's another flaw as QVariant values are mutable and QObjects are not. You should only store a pointer to a QObject within a property.

class PropVal : public QObject {
  Q_PROPERTY(int val READ ... WRITE ...);
  // ...
};
 
class ABC : public QObject {
  Q_PROPERTY(QObject* abc READ ... WRITE ...);
  // ...
};
// ...
ABC abc;
PropVal *prop = qobject_cast<PropVal*>(qvariant_cast<QObject*>(abc.property("abc")));
if(prop) {
  int val = prop->property("val").toInt();
}

class PropVal : public QObject {
  Q_PROPERTY(int val READ ... WRITE ...);
  // ...
};

class ABC : public QObject {
  Q_PROPERTY(QObject* abc READ ... WRITE ...);
  // ...
};
// ...
ABC abc;
PropVal *prop = qobject_cast<PropVal*>(qvariant_cast<QObject*>(abc.property("abc")));
if(prop) {
  int val = prop->property("val").toInt();
}

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