QString to int

[itallor]

Hello everyone, i'm trying to develop an program that validate a string that will have just numbers, but to do this i need to make the string become an int number array, i'm using a mask that just allows the user to insert numbers, and i replaced all special characters like "." , "-" that i used in the mask and my string now is just numbers.

Like the code:

ui->lineEdit->setInputMask("000.000.000-00");
 
QString cpf = ui->lineEdit->text();
cpf.replace(".","");
cpf.replace("-","");

ui->lineEdit->setInputMask("000.000.000-00");

QString cpf = ui->lineEdit->text();
cpf.replace(".","");
cpf.replace("-","");

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Please help me make my string become an int array, because i need to work with each number at a time to compare them and validate the whole number!

Thank you very much!

[FelixB]

why don't you use several LineEdits for the input? Then you can install an QIntValidator on each LineEdit and convert the input with QString::number()

[Zlatomir]

You just need to validate, or do you need the numbers for further calculations?
If you want just validation you can use QRegExp

And if you want integers you can use the split member function, witch returns a QStringList, and then iterate the list and use toInt

[itallor]

You just need to validate, or do you need the numbers for further calculations?
If you want just validation you can use QRegExp

And if you want integers you can use the split member function, witch returns a QStringList, and then iterate the list and use toInt

I'll need the numbers for further calculation, the validation will be made under those calculations.

Thank you very much i'll try it.

Edit: I tried to do what you said but i couldn't can you please help me! I need each number to an calculation! Thanks again!

[Zlatomir]

What part you couldn't do?

If you have the QString, you can do the following:

QString str = "11.22.33";
 
     QStringList list1 = str.split(".");
//the list1 will be a list that contains three strings "11", "22" and "33"

QString str = "11.22.33";

     QStringList list1 = str.split(".");
//the list1 will be a list that contains three strings "11", "22" and "33"

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Then you need to iterate over the QStringList and use toInt() on the strings that it contains:

//maybe you will need some data structure (for example a QVector) that will contain the integers
     QVector<int> vec;
 
     QStringList::Iterator iterator;
     for (iterator = list1.begin(); iterator != list1.end(); ++iterator)
         //add the int to the QVector
         vec.push_back(iterator->toInt());
//Then you have all the values in the QVector vec

//maybe you will need some data structure (for example a QVector) that will contain the integers
     QVector<int> vec;

     QStringList::Iterator iterator;
     for (iterator = list1.begin(); iterator != list1.end(); ++iterator)
         //add the int to the QVector
         vec.push_back(iterator->toInt());
//Then you have all the values in the QVector vec

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[wysota]

This thread is just taking too long.

ui->lineEdit->setInputMask("000.000.000-00");
//...
QString cpf = ui->lineEdit->text();
QRegExp rx("(\\d{3})\\.(\\d{3})\\.(\\d{3})-(\\d{2})");
if(!rx.exactMatch(cpf)){
  // something wrong
}
QVector<int> vals;
for(int i = 1; i<=rx.captureCount();i++){
  vals << rx.cap(i).toInt();
}
return someCheck(vals); // check the values here

ui->lineEdit->setInputMask("000.000.000-00");
//...
QString cpf = ui->lineEdit->text();
QRegExp rx("(\\d{3})\\.(\\d{3})\\.(\\d{3})-(\\d{2})");
if(!rx.exactMatch(cpf)){
  // something wrong
}
QVector<int> vals;
for(int i = 1; i<=rx.captureCount();i++){
  vals << rx.cap(i).toInt();
}
return someCheck(vals); // check the values here

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Wrap this all into a validator api and set it on the line edit.

[itallor]

Thank you everyone, to lead me to the right way!

I tried what wysota said but it didn't work like i expected, because what i needed was that all my numbers became one position at my Vector<int> so i did my QRegExp like this:

QRegExp rx("(\\d{1})(\\d{1})(\\d{1})(\\d{1})(\\d{1})(\\d{1})(\\d{1})(\\d{1})(\\d{1})(\\d{1})(\\d{1})");
 
    if(!rx.exactMatch(cpf))
        ui->okButton->setEnabled(false);
 
    QVector<int> cpfV;
 
    for(int i=1;i<=rx.captureCount();i++)
        cpfV << rx.cap(i).toInt();

QRegExp rx("(\\d{1})(\\d{1})(\\d{1})(\\d{1})(\\d{1})(\\d{1})(\\d{1})(\\d{1})(\\d{1})(\\d{1})(\\d{1})");

    if(!rx.exactMatch(cpf))
        ui->okButton->setEnabled(false);

    QVector<int> cpfV;

    for(int i=1;i<=rx.captureCount();i++)
        cpfV << rx.cap(i).toInt();

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And the QRegExp that you gave me was making a vector with 4 elements, but it helped me a lot, thank you so much! And i would like to know if is there anyway of making this QRegExp smaller?

[wysota]

You can definitely skip the "{1}" parts. But in general you can substitute the second part of my code with:

QStringList strList = rx.capturedTexts();
strList.removeFirst();
qlonglong val = strList.join('').toLongLong();

QStringList strList = rx.capturedTexts();
strList.removeFirst();
qlonglong val = strList.join('').toLongLong();

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Hmm... or maybe I misunderstood what you wanted... I don't really see any sense of all this.

[MattPhillips]

what i needed was that all my numbers became one position at my Vector<int>

What do you mean?