QX11EmbedContainer problem

[yumiko]

I have a similiar problem.

If I use "QProcess" to invoke an external application, how can I get the winId of that application?

[marcel]

You have to iterate through all the windows until you find it.

[wysota]

Either use X11 calls to get it or ask the process for it. Maybe it has a way of telling you its winId.

[marcel]

Either use X11 calls to get it or ask the process for it. Maybe it has a way of telling you its winId.

He can use at most the PID of the process.

[wagmare]

I have a similiar problem.

If I use "QProcess" to invoke an external application, how can I get the winId of that application?

this system call works fine after we start the external program by QProcess : xwininfo -root -all | grep ' " Window Title " ' |awk '{print $1}'

Window title is the running QProcess execution's title

[in_dbasu]

I am using the the container for a xEmbed Widget in the same scope and expect the widget to get embedded in the container but i am getting two window not a single window, the code is like this...
int main(int argc, char*argv[])
{
QApplication app(argc,argv)
QX11EmbedContainer container;
QX11EmbedWidget window;
container.show();
window.embedInto(container.WinID());
container.embedclient(window.winID());
int status= app.exec();
return status;
}

Ideally i shud be getting only a single window but i am getting two separate window.

What could be the problem????????