It probably won't emit finished() then.
Every slot is "implicitely" virtual if redeclared in a subclass. That's a side effect of how signals and slot mechanism works.Oh, BTW QThread::quit() is not virtual, neither is exit.
No, it'll call the "youngest" implementation that has been declared as a slot. Of course this only applies to a situation when the method is called as a result of signal emission and not directly.So I'm not sure how correct it is to reimplement it. Anyway, if qt uses your class, it will call the base class version.






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